# If #e^4x-e=0# what is #x#? Alternately, if #e^(4x)-e=0# what is #x#?

##### 2 Answers

Sep 19, 2016

#### Explanation:

Given

then

and (after dividing both sides by

(Using a calculator for an approximation:

Sep 19, 2016

#### Explanation:

#e^(4x)-e=1 " and adding e to both sides"#

#e^(4x)=e^1" and since the bases (e) are equal, then"#

#4x=1rArrx=1/4#