Re: Orthogonality question


DFisch
 

Jimmy, best explanation of OE I have ever seen or heard, great post!

On Fri, Nov 1, 2019 at 00:26 jimmyjujames <jimmy_an@...> wrote:
If OE is short for orthogonality error.
 
An Orthogonality error (OE) is only east-west when pointing at zenith.
OE is always in line with the counter-weight shaft.
When pointing at NCP with counter-weight shaft pointing down, OE is north-south.
 
 What is an orthogonality error (OE)?
 
 With the counter-weights down and scope pointing at NCP.
 An orthogonality error will cause the viewing point to be above or below NCP.
 
 To the left or right of NCP is not an error.
 You can move Dec to remove any left or right offset.
 
 Rotating RA will move the viewing point around NCP forming a circle around NCP.
 Radius of this circle is your (1x) orthogonality error.
 Diameter of the circle is 2 times (2x) your orthogonality error.
 
 If you move the counter-weight shaft to west side and horizontal/level with ground, the scope's 
 viewing point will be either east or west of NCP by (1x) your orthogonality error.
 If you move scope from NCP to zenith to Dec=0 to SCP, your scope's viewing point will be east or
 west of meridian by your 1x orthogonality error everywhere along that path.
 
 If you do a meridian flip at NCP, you will miss NCP by 1x on the other side of NCP.
 1x on one side of NCP, meridian flip and 1x off on other side = 2x orthogonality error when
 flipping from east to west side.
 
 You will have to shim the front or rear ring to bring your viewing point back to NCP.
 
 After minimizing your orthogonality error,
 future meridian flips should result in star in FOV on both sides.
 
 If not then you may have flexure and/or worm needs re-meshing and/or
 something is loose and needs tightening.
 
As always, I may be wrong again.
Jimmy

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